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Sagot :
Answer:
x = [tex]\frac{3}{20}[/tex]
Step-by-step explanation:
Given
x + [tex]\frac{3}{2}[/tex] + (x - 1) = [tex]\frac{4}{5}[/tex]
Multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions
10x + 15 + 10(x - 1) = 8
10x + 15 + 10x - 10 = 8
20x + 5 = 8 ( subtract 5 from both sides )
20x = 3 ( divide both sides by 20 )
x = [tex]\frac{3}{20}[/tex]
x + 3/2 + x - 1 = 4/5
Collect the same terms
x + x + 3/2 - 1 = 4/5
2x + 3/2 - 2/2 = 4/5
2x + (3 - 2)/2 = 4/5
2x + 1/2 = 4/5
2x + 0.5 = 0.8
Subtract both sides 0.5
2x + 0.5 - 0.5 = 0.8 - 0.5
2x + 0 = 0.3
2x = 3/10
Divide both sides by 2
2x ÷ 2 = ( 3/10 ) ÷ 2
x = 3/10 × 1/2
x = 3/20
_________________________________
Check :
3/20 + 3/2 + ( 3/20 - 1 ) = 4/5
3/20 + 30/20 + ( 3/20 - 20/20 ) = 4/5
(3 + 30)/20 + (3 - 20)/20 = 4/5
33/20 - 17/20 = 4/5
(33 - 17)/20 = 4/5
16/20 = 4/5
4 × 4 / 4 × 5 = 4/5
4/5 = 4/5
Thus we found the correct value of x .
And we're done...
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