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Someone tell me where everyone is going right please !!

Someone Tell Me Where Everyone Is Going Right Please class=

Sagot :

Answer:

1. 3rd option

2. 4th option

3. 1st option

4. 2nd option

5. 2nd option

Step-by-step explanation:

1.

on changing the signs of an equality the sign gets reveresd

-6 < -2x

6 > 2x

3 > x

2.

2x - 3 > 11 - 5x

  • adding 5x and 3 to both sides and combining like terms

(2x + 5x) + (-3 + 3) > (11 + 3) + (-5x + 5x)

7x > 14

x > 2

put of all the options x = 4 is a value greater than 2 thus satisfying the condition.

3.

6k + 10. 5 = 3k + 12

  • subtracting 3k and 10.5 from both the sides while combining like terms

(6k - 3k) + (10.5 - 10.5) = (3k - 3k) + (12 - 10.5)

3k = 1.5

k = 0.5

4.

y + 3 = -y + 9

  • adding y and subtracting 3 from both sides

(y + y) + (3 - 3) = (-y + y) + (9 - 3)

2y = 6

y = 3

5.

-9x + 1 = -x + 17

adding x and subtracting 1 from both sides

(-9x + x) + (1 -1) = (-x +x) + (17 -1)

-8x = 16

multiplying the equation by -1

8x = -16

diving both sides by 8

x = -2

Answer:

[tex]1. \: \: x < 3[/tex]

[tex]2. \: \: 2[/tex]

[tex]3. \: \: k = 0.5[/tex]

[tex]4. \: \: y = 3[/tex]

[tex]5. \: \: x = 12[/tex]

Step-by-step explanation:

[tex]1. \: \: - 2(5 - 4x) < 6x - 4 \\ - 10 + 8x < 6x - 4 \\ - 10 + 2x < - 4 \\ 2x < 6 \\ x < 3[/tex]

[tex]2. \: \: 2x - 3 > 11 - 5x \\ 7x - 3 > 11 \\ 7x > 14 \\ x = 2[/tex]

[tex]3. \: \: 6k + 10.5 = 3k + 12 \\ 3k + 10.5 = 12 \\ 3k = 1.5 \\ k = 0.5[/tex]

[tex]4. \: \: y + 3 = - y + 9 \\ 2y + 3 = 9 \\ 2y = 6 \\ y = 3[/tex]

[tex]5. \: \: - 9x + 1 = - x + 17 \\ - 8x + 1 = 17 \\ - 8x = 16 \\ x = - 2[/tex]

Hope it is helpful....

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