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Sagot :

MrRoyal

Answer:

(b) [tex]x \ge -3[/tex]

Step-by-step explanation:

Given

[tex]g(x) = \sqrt{x + 3}[/tex]

Required

The domain

For [tex]g(x) = \sqrt{x + 3}[/tex] to be defined, the following must be true

[tex]\sqrt{x + 3} \ge 0[/tex]

Square both sides

[tex]x + 3 \ge 0[/tex]

Subtract 3 from both sides

[tex]x \ge -3[/tex]

Hence, the domain is:

(b) [tex]x \ge -3[/tex]

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