Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A 4.0-kg meatball is moving to the right with a speed of 6.0 m/s directly toward a 2.0 kg meatball
which is at rest. The two meatballs collide and stick together. What is their velocity immediately after
the collision?

Sagot :

Luv2Teach

Answer:

Explanation:

The equation for this is the one for the Law of Momentum Conservation which says that the momentum before the collision of the balls has to be the same after the collision because momentum cannot be created or destroyed. For us in particular:

[tex][(m_1v_1+m_2v_2)]_b=[(m_1+m_2)v_{both}]_a[/tex] and filling in:

[(4.0)(6.0) + (2.0)(0)] = [(4.0 + 2.0)v] and

24 + 0 = 6.0v and

24 = 6.0v so

v = 4.0 m/s to the right

We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.