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Sagot :
Answer:
Ok... I hope this is correct
Step-by-step explanation:
Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^(2)+y^(2)=16
Center: ( 0 , 0 )
Vertices: ( 4 , 0 ) , ( − 4 , 0 )
Foci: ( 4 √ 2 , 0 ) , ( − 4 √ 2 , 0 )
Eccentricity: √ 2
Focal Parameter: 2 √ 2
Asymptotes: y = x , y = − x
Then 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1.
Simplified
0 ≤ z ≤ 1 , x ^2 + y ^2 + z ^2 − 2 ^z + 1 = 16 , z ≥ 1
For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.
Vector:
csc ( x ) , x = π
cot ( 3 x ) , x = 2 π 3
cos ( x 2 ) , x = 2 π
Since
( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x ^2 ) is constant with respect to F , the derivative of ( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x 2 ) with respect to F is 0 .
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