Answer:
[tex]{ \bf{let \: \: { \tt{ - {x}^{2} + 5x + 24} \: \: be \: \: { \bf{{y}}}}}} \\ { \tt{y = - {x}^{2} + 5x + 24 }} \\ { \tt{y = (x + 3)(x - 8)}} \\ for \: x - intercept : y = 0 \\ { \tt{(x + 3)(x - 8) = 0}} \\ { \bf{x = - 3 \: and \: 8}}[/tex]
The factors to the given expression are -1(x+3)(x-8)
The x-intercepts are -3, 8
Factorization is the process in which we write an expression in its factors which when multiplied results in the original expression.
We equate the given expression to f(x)
(-x² + 5x + 24) = f(x)
⇒ -1(x² - 5x - 24) = f(x)
⇒ -1(x² - (8-3)x - 24) = f(x)
⇒ -1(x² + 3x - 8x -24) = f(x)
⇒ -1(x(x+3) -8(x+3)) = f(x)
⇒ -1(x+3)(x-8) = f(x)
∴The factor to the given expression is -1(x+3)(x-8)
To find the x-intercepts we equate f(x) = 0
⇒ -1(x+3)(x-8) = 0
⇒ (x+3)(x-8) = 0
x-intercepts are the roots of the above equation.
∴ The x-intercepts occur where x = -3 and x = 8
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