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Find sin A, round to the nearest hundredth.

Find Sin A Round To The Nearest Hundredth class=

Sagot :

wegnerkolmp2741o

Answer:

.92

Step-by-step explanation:

sin A = opp side/ hypotenuse

       

We can use the Pythagorean theorem to find the hypotenuse

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

3^2 +7^2 = AC ^2

9+49 = AC ^2

58 = AC^2

Taking the square root

sqrt(58) = hypotenuse

sin A = 7/sqrt(58)

sin A =.91914503

sin A = .92

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