antonio281710
Answered

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(7x^2y^3)(3x^5y^8)

Sagot :

paridhibahakari

Step-by-step explanation:

First, we put the expressions in multiplication form:

(7x2y3)×(3x5y8)(7x2y3)×(3x5y8)

We multiply like terms:

(7x2×3x5)(y3×y8)(7x2×3x5)(y3×y8)

We multiply the coefficients and add the exponents:

21x2+5y3+821x2+5y3+8

Solving, we obtain:

21x7y11

leena

Hello!

[tex]\large\boxed{21x^7y^{11}}}[/tex]

(7x²y³)(3x⁵y⁸)

Multiply by ADDING exponents with the same base:

(7 * 3) (x² * x⁵) (y³ * y⁸)

21 * x² ⁺ ⁵ * y³ ⁺ ⁸

Simplify:

21 * x⁷ * y¹¹

21x⁷y¹¹

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