Answered

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What is an equation of the line that is parallel to y = 3x - 8 and passes
through the point (4,-5)?

Sagot :

Answer:

[tex]y=3x-17[/tex]

Step-by-step explanation:

Parallel equations always share a slope.

So since we know the slope and a point the equation needs to pass through we can plug in the values and replace -8 with [tex]b[/tex]

[tex]-5=3(4)+b[/tex]

simplify both sides

[tex]-5=12+b[/tex]

isolate the variable

[tex]-17=b[/tex]

plug [tex]b[/tex] back into the equation and you get

[tex]y=3x-17[/tex]

maqsoodquadri1

Answer:

y = 3 x + 11

 Explanation:

Parallel lines have the same slopes.

The slope of the new line will have the same slope as the given line:

y = 3 x − 4

⇒ m = 3

One point on the line is given,  

( − 2  5 ) .

This is  ( x 1  y 1 )

The formula for slope is  

m = ( change in y values/ change in x-values ) =  y 2  −  y 1/ x 2 − x 1

If you have the slope and one point , substitute them into a formula which is based on the formula for slope given above.

y  −  y 1 =  m  ( x  −  x 1 )  

y  −  5  =  3 ( x  −  ( − 2 ) )

y  −  5  =  3 ( x + 2 )

Simplify to get the required equation of the line.

y  =  3 x  +  6  +  5

y  =  3 x  +  11

Step-by-step explanation:

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