Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

It takes 130 j of work to compress a certain spring 0.10m. (a) what is the force constant of this spring? To compress the spring an additional 0.10m, does it take 130

Sagot :

Luv2Teach

Answer:

Explanation:

The PE equation for a mass/spring system is

[tex]PE=\frac{1}{2}k[/tex]Δx² and filling in:

[tex]130=\frac{1}{2}k(.10)^2[/tex] and

[tex]k=\frac{2(130)}{(.10)^2}[/tex] so

k = 26000 N/m

If the displacement from equilibrium changes more, the PE needed to compress it will also change.

[tex]PE=\frac{1}{2}(26000)(.20)^2[/tex] gives us that

PE = 520J

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.