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Sagot :
Answer:
The average value of the cost function over the interval is of $23,500.
Step-by-step explanation:
Average value of a function:
The average value of a function, over an inteval [a,b], is given by:
[tex]A = \frac{1}{b-a} \int_{a}^{b} f(x) dx[/tex]
In this case:
Function [tex]C(x) = 20000 - 10x[/tex], interval with [tex]a = 0,b = 700[/tex]
So
[tex]A = \frac{1}{700} \int_{0}^{700} 20000+10x dx[/tex]
[tex]A = \frac{1}{700} (20000x+5x^2)|_{0}^{700}[/tex]
So
[tex]A = \frac{20000(700)+5(700)^2}{700} = 23500[/tex]
The average value of the cost function over the interval is of $23,500.
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