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Sagot :
Answer:
[tex]2\sqrt{2x}[/tex] or [tex]8x^2[/tex]
Step-by-step explanation:
first you find the distance between P and O which is 4n (use the distance formula -- [tex]\sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)}[/tex])
then find the distance between O and Q also using the distance formula; it gives you 4n
then find the hypotunuse by using the pythagorean theorem, [tex]a^2+b^2=c^2[/tex] which would be [tex]4n^2+4n^2=hypotenuse[/tex] and when you simplify it, you get [tex]8x^2[/tex] and if you need it in radical form, it would be [tex]2\sqrt{2x}[/tex]
Answer:
[tex]Hypotenuse = 4n \sqrt{2} [/tex]
Step-by-step explanation:
Catethus1=4n
Catethus2=4n
Hypotenuse=?
[tex]Hypotenuse= \sqrt{{(catethus1)}^{2} + {(catethus2)}^{2}} \: = \sqrt{{(4n)}^{2} + {(4n)}^{2}} \: = 4n \sqrt{2} [/tex]
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