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What is the area of trapezoid DEFG with coordinates D (2, 3), E (5, 3), F (3, 1), and G (2.1)? O 2 square units O 3 square units O 4 square units 8 square units​

Sagot :

Answer:

4

Step-by-step explanation:

took test

The area of trapezoid DEFG with coordinates D (2, 3), E (5, 3), F (3, 1), and G (2,1) is 4 square units.

Area of a trapezoid:

The formula for the area of a trapezoid is,

Area = {(a + b) × h} / 2

Where a and b are the parallel sides and h is the perpendicular distance (height) between them.

But this formula only works when these a, b and h values are given.

In the figure below we can easily find those a, b and h values.

  1. h (FH) = 2 units.
  2. a (GF) = 1 units.
  3. b (DE) = 3 units.

Now using the formula we get,

Area = 1/2 × (1 + 3) × 2

Simplifying (1 + 3) we get,

Area = 1/2 × 4 × 2

Further simplifying, 1/2 and 2 will get cancelled,

Area = 4 square units

Therefore, the area of trapezoid DEFG is 4 square units.

Look more about how the area of a trapezoid can be calculated when coordinates are given here - brainly.com/question/26277437

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