Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

What is the area of trapezoid DEFG with coordinates D (2, 3), E (5, 3), F (3, 1), and G (2.1)? O 2 square units O 3 square units O 4 square units 8 square units​

Sagot :

Answer:

4

Step-by-step explanation:

took test

The area of trapezoid DEFG with coordinates D (2, 3), E (5, 3), F (3, 1), and G (2,1) is 4 square units.

Area of a trapezoid:

The formula for the area of a trapezoid is,

Area = {(a + b) × h} / 2

Where a and b are the parallel sides and h is the perpendicular distance (height) between them.

But this formula only works when these a, b and h values are given.

In the figure below we can easily find those a, b and h values.

  1. h (FH) = 2 units.
  2. a (GF) = 1 units.
  3. b (DE) = 3 units.

Now using the formula we get,

Area = 1/2 × (1 + 3) × 2

Simplifying (1 + 3) we get,

Area = 1/2 × 4 × 2

Further simplifying, 1/2 and 2 will get cancelled,

Area = 4 square units

Therefore, the area of trapezoid DEFG is 4 square units.

Look more about how the area of a trapezoid can be calculated when coordinates are given here - brainly.com/question/26277437

#SPJ2

View image prachikalantri