Answer:
Step-by-step explanation:
They appear to be linear so that's easy enough to find out. What we are being asked is to find the equation represented by each table. Knowing that they are linear, we need the slope of each one and then the y-intercept of each one (each "one" being each table). Let's begin with the y-intercept. The y-intercepts exist where x = 0. In the first table, where x = 0, y = -4; in the second table, where x = 0, y = 3.
The equation we will finally fill in is y = mx + b, where m is the slope and b is the y-intercept.
Solving for slope in the first table:
[tex]m=\frac{-4-(-7)}{0-(-1)}=\frac{3}{1}=3[/tex] and the equation for this table is
y = 3x - 4
Solving for the slope in the second table:
[tex]m=\frac{3-4}{0-(-1)}=\frac{-1}{1}=-1[/tex] and the equation for this table is
y = -1x + 3 or just y = -x + 3
That's the system, which happens to be choice D
