Answered

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Find domain of (x^2+3)+[tex]\sqrt{x} 3x-1[/tex]

Sagot :

s20109293775

Answer:

= x^2 + 3 + √3x^2 - 1

Step-by-step explanation:

Remove parentheses: (a) = a

= x^2 + 3 + √x . 3x - 1

x . 3x = 3x^2

= x^2 + 3 + √3x^2 - 1

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