krj275106
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

What is the vertex of f(x) = x^2 + 10x + 16?

Sagot :

luana
[tex]f(x)=x^2+10x+16\\\\V(-\frac{b}{2a},-\frac{\Delta}{4a})-vertex\\\\-\frac{b}{2a}=-\frac{10}{2\cdot1}=-5\\\\\Delta=b^2-4ac\\\Delta=10^2-4\cdot1\cdot16=100-64=36\\\\-\frac{\Delta}{4a}=-\frac{36}{4\cdot1}=-9\\\\V(-5,-9)[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.