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Sagot :
Answer:
x = -0.70,-2.212.
Step-by-step explanation:
(a) The quadratic equation is :
[tex]6x^2 + 17x + 9 = 0[/tex]
Here,
a = 6, b = 17, c = 9
Put all the values in the quadratic formula.
[tex]x=\dfrac{-17+\sqrt{17^2-4\times 6\times 9}}{2(6)},\dfrac{-17-\sqrt{17^2-4\times 6\times 9}}{2(6)}\\\\x=-0.70,-2.12[/tex]
So, the solution of the given equation are -0.70,-2.212.
(b) Equation is : [tex]4x^2 -4x + 1 = 0[/tex].
Here, a = 4, b = -4 and c = 1
So,
[tex]x=\dfrac{-(-4)+\sqrt{(-4)^2-4\times 4\times 1}}{2(4)},\dfrac{-(-4)-\sqrt{(-4)^2-4\times 4\times 1}}{2(4)}\\\\x=0.5,0.5[/tex]
Hence, this is the required solution.
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