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Sagot :
Answer:
5 / 648
Step-by-step explanation:
Given tbe sample space for a pair of dice attached below :
Sample space for a pair of dice = 6² = 36
Rolling a 3 first :
Recall, probability = required outcome / Total possible outcomes
P(rolling a 3). = 2 / 36 = 1 /18
Probability of rolling a 6 (second roll)
P(rolling a 6) = 5 / 36
Hence,
P(3) then P(6) ;
1 / 18 * 5/36 = 5 / 648
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