Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The three sides of triangle ΔBDA are equal to the three sides of triangle ΔBDC.
- The congruency theorem that can be used to prove ΔBDA ≅ ΔBDC is; SSS
Reasons:
The given parameters are;
The common side to ΔBDA and ΔBD = BD
BC ≅ BA
AD ≅ DC
The two column proof is presented as follows;
Statement [tex]{}[/tex] Reasons
BC ≅ BA [tex]{}[/tex] Given
AD ≅ DC [tex]{}[/tex] Given
BD ≅ BD [tex]{}[/tex] By reflexive property
Therefore, we have;
- ΔBDA ≅ ΔBDC [tex]{}[/tex] By Side-Side-Side SSS, congruency rule
The congruency theorem that can be used to prove ΔBDA ≅ ΔBDC is therefore;
- SSS
The Side-Side-Side congruency rule states that if three sides of on triangle are congruent to three sides of another triangle, then the two triangles are congruent.
Learn more about Side-Side-Side, SSS congruency rule here:
https://brainly.com/question/10684250
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.