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Sagot :
The three sides of triangle ΔBDA are equal to the three sides of triangle ΔBDC.
- The congruency theorem that can be used to prove ΔBDA ≅ ΔBDC is; SSS
Reasons:
The given parameters are;
The common side to ΔBDA and ΔBD = BD
BC ≅ BA
AD ≅ DC
The two column proof is presented as follows;
Statement [tex]{}[/tex] Reasons
BC ≅ BA [tex]{}[/tex] Given
AD ≅ DC [tex]{}[/tex] Given
BD ≅ BD [tex]{}[/tex] By reflexive property
Therefore, we have;
- ΔBDA ≅ ΔBDC [tex]{}[/tex] By Side-Side-Side SSS, congruency rule
The congruency theorem that can be used to prove ΔBDA ≅ ΔBDC is therefore;
- SSS
The Side-Side-Side congruency rule states that if three sides of on triangle are congruent to three sides of another triangle, then the two triangles are congruent.
Learn more about Side-Side-Side, SSS congruency rule here:
https://brainly.com/question/10684250
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