Answer:
A)
Data:
P = 6.5 cm
B = 2.4 cm
H = ?
▪ [tex]H^{2} = P^{2} + B^{2}[/tex]
=> [tex]H^{2} = 6.5^{2} cm+ 2.4^{2}[/tex] cm
=> [tex]H^{2}[/tex] = 48.01 cm
=> H = [tex]\sqrt{48.01}[/tex] cm
=> H = 6.92 cm
Ans: the length of the hypotenuse is 6.92 cm.
B)
Data:
P = [tex]\frac{1}{4}[/tex]
H = [tex]\frac{1}{3}[/tex]
B = ?
▪ [tex]H^{2} = P^{2} + B^{2}[/tex]
=> [tex]\frac{1}{3}^{2}[/tex] cm = [tex]\frac{1}{4}^{2}[/tex] cm+ [tex]B^{2}[/tex]
=> 0.11 cm = 0.06 cm + [tex]B^{2}[/tex]
=> [tex]B^{2}[/tex] = 0.11 cm - 0.06 cm
=> B = [tex]\sqrt{0.05}[/tex] cm
=> B = [tex]\frac{11}{50} [/tex] cm
Ans: the length of the other side is [tex]\frac{11}{50} [/tex] cm.
