At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Identify an equation in point-slope from for the line perpendicular to y=-4x-1 that passes through (-2, 4)​

Identify An Equation In Pointslope From For The Line Perpendicular To Y4x1 That Passes Through 2 4 class=

Sagot :

Answer:

y - 4 = ¼(x + 2)

Step-by-step explanation:

Point-slope form equation is given as y - b = m(x - a). Where,

(a, b) = a point on the line = (-2, 4)

m = slope = ¼ (sleep of the line perpendicular to y = -4x - 1 is the negative reciprocal of its slope value, -4 which is ¼)

✔️To write the equation, substitute (a, b) = (-2, 4), and m = ¼ into the point-slope equation, y - b = m(x - a).

y - 4 = ¼(x - (-2))

y - 4 = ¼(x + 2)

None of the options are correct