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Sagot :
Answer:
The answer is "This direct variant (-4,2) is part of it".
Step-by-step explanation:
The equation expresses its direct variation relation
[tex]y = mx ........ (1)[/tex]
Where x and y vary directly, and k vary continuously.
Now so the point (4,-2) is in the direct relation of variation, so from equation (1) we are given,[tex]-2 = 4m[/tex]
[tex]\to m=-\frac{1}{2}[/tex]
The equation (1) is therefore converted into
[tex]\to y=-\frac{1}{2}x \\\\\to x + 2y = 0 ......... (2)[/tex]
Then only the point (-4,2) satisfies the connection with the four possibilities (2). Therefore (-4,2) is a direct variant of this.
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