At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
5 gram of 197 Au contain 1.53*10^22 atoms. so just multiply that with 59 to get 295 grams :)
The molar mass of gold, Au, as seen on the periodic table, is 196.97 grams per mole. So, do this to find the number of moles in a 295 gram sample:
[tex](295g\ Au)(\frac{1mol\ Au}{196.97g\ Au}) = 1.49769mol\ Au[/tex]
So, a 295 gram sample of gold has about 1.5 moles of gold in it.
To find the number of atoms, multiply the number of moles by Avogadro's number:
[tex](1.49769mol\ Au)(\frac{6.022*10^{23}\ atoms}{mol}) = 9.02 * 10^{23}\ atoms\ Au[/tex]
[tex](295g\ Au)(\frac{1mol\ Au}{196.97g\ Au}) = 1.49769mol\ Au[/tex]
So, a 295 gram sample of gold has about 1.5 moles of gold in it.
To find the number of atoms, multiply the number of moles by Avogadro's number:
[tex](1.49769mol\ Au)(\frac{6.022*10^{23}\ atoms}{mol}) = 9.02 * 10^{23}\ atoms\ Au[/tex]
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.