Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A) How many moles of gold atoms are present in a 295-gram sample of gold? B) How many gold atoms would there be in the sample?

Sagot :

5 gram of 197 Au contain 1.53*10^22 atoms. so just multiply that with 59 to get 295 grams :)
The molar mass of gold, Au, as seen on the periodic table, is 196.97 grams per mole. So, do this to find the number of moles in a 295 gram sample:

[tex](295g\ Au)(\frac{1mol\ Au}{196.97g\ Au}) = 1.49769mol\ Au[/tex]

So, a 295 gram sample of gold has about 1.5 moles of gold in it.

To find the number of atoms, multiply the number of moles by Avogadro's number:

[tex](1.49769mol\ Au)(\frac{6.022*10^{23}\ atoms}{mol}) = 9.02 * 10^{23}\ atoms\ Au[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.