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use elimination to solve system of equations

5m-2p=24
3m+2p=24

Sagot :

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[tex]5m-2p=24 \\ \underline{3m+2p=24} \\ 5m+3m+2p-2p=24+24 \\ 8m=48 \\ m=6 \\ \\ 5m-2p=24 \\ 5 \times 6-2p=24 \\ 30-2p=24 \\ -2p=24-30 \\ -2p=-6 \\ p=3 \\ \\ \hbox{the answer:} \\ m=6 \\ p=3[/tex]
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5m-2p=24 (label equation 1)
3m+2p=24 (label equation 2)

equation 1 + equation 2--> 8m=24
                                         m=3 ( i divided by 8 to both sides)
sub m=3 into equation 1
5(3)-2p=24
15-2p=24
-2p=9 ( i subtracted 15 to both sides)
p=9/-2 ( i divided by -2 to both sides)
p=-9/2

therefore m=3 and p=-9/2

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