Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
(a) The wavelength of the electron is 202.25885 nm
(b) The minimum energy required to remove the electron is 1.6565 × 10⁻¹⁷ J
(c) The wavelength of the causing radiation is approximately 8.84 nm
(d) X-ray
The question parameters are;
The given parameters of the electron are;
The velocity of the electron, v = 3.6 × 10³ km/s
(a) de Broglie wavelength is given as follows;
λ = h/(m·v)
Where;
λ = The wavelength of the wave
h = Planck's constant = 6.626 × 10⁻³⁴ J·s
m = The mass of the electron = 9.1 × 10⁻³¹ kg
Therefore, we get;
λ = 6.626 × 10⁻³⁴/(9.1 × 10⁻³¹ × 3.6 × 10⁶) = 202.25885 × 10⁻⁶
The wavelength, λ, of the electron is 202.25885 × 10⁻⁶ m = 202.25885 nm
(b) The energy required to remove the electron from the metal surface is known as the work function, W₀, which is given by the following formula
W₀ = h·f₀
Where;
f₀ = The threshold frequency
Given that the threshold frequency, f₀ = 2.50 × 10¹⁶ Hz, we have;
W₀ = 6.626 × 10⁻³⁴ J·s × 2.50 × 10¹⁶ Hz = 1.6565 × 10⁻¹⁷ J
The energy required to remove the electron from the metal surface, W₀ = 1.6565 × 10⁻¹⁷ J
(c) The wavelength of the radiation that caused the photoejection of the electron is given as follows;
The energy of the incoming photon, E = W₀ + (1/2)·m·v²
Where;
v = The velocity of the electron, and m = The mass of the electron
Therefore;
E = 1.6565 × 10⁻¹⁷ + (1/2) × 9.1 × 10⁻³¹ kg × (3.6 × 10⁶ m/s)² = 2.24618 × 10⁻¹⁷ J
We have;
E = h·f
∴ f = (2.24618 × 10⁻¹⁷ J)/(6.626 × 10⁻³⁴ J·s) = 3.38994869 × 10¹⁶ Hz
The speed of light, c = 299,792,458 m/s
From the equation for the speed of light, we have;
λ = c/f
∴ λ = (299,792,458 m/s)/(3.38994869 × 10¹⁶ Hz) = 8.84356919 nm ≈ 8.84 nm
The wavelength of the radiation that caused photoejection of the electron, λ[tex]_{causing \ radiation}[/tex] ≈ 8.84 nm
(d) The kind of electromagnetic radiation used which has a wavelength of 8.84 nm is the X-Ray which are electromagnetic radiation having wavelengths that extend from 10 picometers to 10 nanometers.
Learn more about De Broglie wavelength here;
https://brainly.com/question/19131384
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.