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I need help please, show work

I Need Help Please Show Work class=

Sagot :

inspirationalgdandyt

Answer:

24 and 32 ft or 32 and 24 ft

Step-by-step explanation:

Perimeter of rectangle(p)=2(l+b)

or, 112/2=l+b

Therefore, l+b=56

Now,

diagonal(d)=40

By pythogoras theorem,

h^2=p^2+b^2 (d=h here)

40^2=l^2+b^2

Now,

Square l+b=56

(l+b)^2=56^2

l^2+2lb+b^2=3136

2lb=3136-1600

lb=1536/2

Therefore, lb=768

b=768/l

Now,

Perimeter of rectangle(p)=2(l+b)

l+b=56

l+768/l=56

l^2+768=56l

l^2+768-56l=0

Factoring,

(l - 32) (l - 24) = 0

Either l= 32 or l = 24

When l=32,

l+b=56

32+b=56

b=24

When l=24

l+b=56

24+b=56

b=32

So the dimensions of the dance floor are 24 and 32 ft or 32 and 24 ft.

Answer:

24 ft x 32 ft

Step-by-step explanation:

[tex]2x+2y=112[/tex]

[tex]\sqrt{x^{2}+y^{2} } =40[/tex]

Graph the equations

Find the point where they intersect

Answer is 24 ft and 32 ft

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