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Sagot :
Answer:
Ann has $30
Ryan has $63
Keith has $21
Step-by-step explanation:
First I assigned variables to the amounts each owns. It doesn't really matter what letters, but I said x represents Ann's money, y represents Ryan's money, and z represents Keith's money.
We know that with all their money added up, they have 114. This gives us our first equation;
114=x+y+z
Ryan has 3 times what Keith has, which, in terms of variables, is
y=3z
Keith has nine dollars less than Ann. Less, in word problems, always means subtraction. This gives us our third equation:
z=x-9
Okay so the impulse is to put z=x-9 and y=3z into the first equation, but the goal is to create an equation with only one variable so this will not work.
What we do instead is sub z=x-9 into y=3z. This gives
y=3(x-9)=3x-27
Now that both y and z are in terms of x, we plug those equations into the first and then solve for x;
114=x+3x-27+x-9
114=5x-36
150=5x
30=x
Now that we know x, we can find z and y using the equations from earlier:
z=30-9=21
y=3(21)=63
x=30, y=63, and z=21, thus Ann has $30, Ryan has $63, and Keith has $21.
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