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3x - 2y = 16 and x - 2y = 4 (any method <3)​

Sagot :

Answer:   (x, y) = (6, 1)

This means x = 6 and y = 1

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Explanation:

I'll use the substitution method to solve this system.

Let's solve the second equation for x

x-2y = 4

x = 4+2y

Then plug that into the first equation so we can solve for y.

3x - 2y = 16

3(4+2y) - 2y = 16 ... x replaced with 4+2y

12+6y - 2y = 16

12 + 4y = 16

4y = 16-12

4y = 4

y = 4/4

y = 1

Lastly, use this y value to find x

x = 4 + 2y

x = 4 + 2(1)

x = 6

The solution as an ordered pair is (x, y) = (6, 1)

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Checking the answer:

Plug those x,y coordinates into the first equation

3x - 2y = 16

3(6) - 2(1) = 16

18 - 2 = 16

16 = 16

That confirms the first equation. Repeat for the second equation

x - 2y = 4

6 - 2(1) = 4

6 - 2 = 4

4 = 4

Both equations are confirmed.

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