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Sagot :
Answer:
Set two equations:
- Number #1 = x
- Number #2 = y
[tex]\left \{ {{x+y=50} \atop {\frac{x}{y}=\frac{7}{11} }} \right.[/tex]
Rearrange one of the equations to find the value of a variable:
[tex]x+y=50\\x=50-y[/tex]
Substitute in that value into the other equation:
[tex]\frac{50-y}{y}=\frac{7}{11}[/tex]
Cross-multiply & solve for y:
[tex]7y=11(50-y) \\7y=550-11y\\7y+11y=550\\18y=550\\y=\frac{550}{18}=\frac{275}{9}[/tex]
Substitute in the value to the original equation to find x:
[tex]\frac{x}{\frac{275}{9}}=\frac{7}{11} \\\frac{9x}{275}=\frac{7}{11} \\9(11)x=275(7)\\99x=1925\\x=\frac{1925}{99} =\frac{175}{9}[/tex]
Therefore, the answer will be:
- x = [tex]\frac{175}{9}[/tex]
- y = [tex]\frac{275}{9}[/tex]
You can check your answers by:
[tex]\frac{175}{9} +\frac{275}{9} =\frac{450}{9} =50[/tex]
[tex]\frac{\frac{175}{9} }{\frac{275}{9} } =\frac{175}{9} *\frac{9}{275} =\frac{175}{275}=\frac{7}{11}[/tex]
Answer:
x = 175/9
y = 275/9
Step-by-step explanation:
Let the larger number be 'x' and smaller number be 'y'
sum of two numbers is 50.
x +y = 50 --------(I)
x = 50 - y -------------(II)
The larger number is divided by the smaller number we get 7/11.
[tex]\frac{x}{y}=\frac{7}{11}\\\\[/tex]
Cross multiply,
11x = 7y
11x - 7y = 0 ------------(III)
Substitute x = 50 -y in equation (III)
11*(50-y) - 7y = 0
11*50 - 11*y - 7y = 0 {Distributive property}
550 - 11y - 7y = 0
550 - 18 y = 0 {Combine like terms}
Subtract 550 from both sides
- 18y = -550
Divide both sides by (-18)
y = -550/-18
y = 275/9
substitute y = 275/9 in equation (III)
[tex]11x - 7*(\frac{275}{9})=0\\\\11x-\frac{1925}{9}=0\\\\11x =\frac{1925}{9}\\\\x=\frac{1925}{9*11}\\\\x=\frac{175}{9}[/tex]
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