Answer:
[tex]y=2x^2+1[/tex]
Step-by-step explanation:
The general equation for a parabola in vertex form is the following:
[tex]y=a(x-h)^2+k[/tex]
Where ([tex]h,k[/tex]) is the parabola's vertex and (a) is the stretch and compression factor. As one can see in the given graph, the parabola has a vertex at (0, 1), moreover, it passes through the point (1, 3). Substitute these points into the equation for the parabole, and simplify,
[tex]y=a(x-h)^2+k[/tex]
Vertex: (0, 1)
[tex]y=a(x-0)^2+1[/tex]
A point on the parabola: (1, 3)
[tex]3=a(1-0)^2+1[/tex]
[tex]3=a1+1\\3 = a + 1\\[/tex]
Inverse operations,
[tex]3=a+1[/tex]
[tex]2 = a[/tex]
Substitute back into the original expression:
[tex]y=a(x-h)^2+k[/tex]
[tex]y=2(x-0)^2+1[/tex]
Simplify to put in standard form:
[tex]y=2(x-0)^2+1[/tex]
[tex]y=2(x)^2+1[/tex]
[tex]y=2x^2+1[/tex]
