Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The volume of a gas was 48 mL when the temperature was 159.6 ºC. If the temperature was initially 4.9 ºC, and there was no change in the pressure, what was the initial volume of the gas?

Sagot :

  • V1=48mL
  • T1=159.6°C
  • T2=4.9°C
  • V2=?

According to Charles law

[tex]\boxed{\sf \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{48}{159.6}=\dfrac{V_2}{4.9}[/tex]

[tex]\\ \sf\longmapsto V_2=\dfrac{48\times 4.9}{159.6}[/tex]

[tex]\\ \sf\longmapsto V_2=\dfrac{235.2}{159.6}[/tex]

[tex]\\ \sf\longmapsto V_2=1.4mL[/tex]