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Question 5 10 pts Which function represents the inverse of f(x) = (x + 6)2 - 5? of 1(1) = V1 + 5 - 6 of '(x) = (x + 5)2 - 6 of '(x) = V1 – 6 + 5 Of '(x) = (x + 6 – 5​

Sagot :

wegnerkolmp2741o

Answer:

f(x)^-1(x) =sqrt(x+5) -6

Step-by-step explanation:

f(x) = (x + 6)^2 - 5

y =  (x + 6)^2 - 5

Exchange x and y and solve for y

x = (y + 6)^2 - 5

Add 5 to each side

x+5 =  (y + 6)^2 - 5+5

x+5 =  (y + 6)^2

Take the square root of each side

sqrt(x+5 )= sqrt( (y + 6)^2 )

sqrt(x+5 )=(y + 6)

Subtract 6 from each side

sqrt(x+5 ) -6=y + 6-6

sqrt(x+5) -6 = y

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