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Please Help I will give you a lot of points if you do!

Please Help I Will Give You A Lot Of Points If You Do class=

Sagot :

Recall that ab   ⇔   ¬ab. So we can write

q ⇒ (pr )   ⇔   ¬q ∨ (pr )

Then the negation of this would be, for instance,

¬(¬q ∨ (pr ))   ⇔   ¬(¬q) ∧ ¬(pr )

…   ⇔   q ∧ (¬p ∨ ¬r )

…   ⇔   (¬pq) ∨ (q ∧ ¬r )

…   ⇔   ¬(p ∨ ¬q) ∨ (q ∧ ¬r )

…   ⇔   (p ∨ ¬q) ⇒ (q ∧ ¬r )

It's impossible to tell what kind of statement your program is expecting, but since there are 5 slots available, my money would be on q ∧ (¬p ∨ ¬r ), so long as ¬p and ¬r are options.