At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Step-by-step explanation:
Find three consecutive odd integers such that the sum of the last two is 15 less than 5 times the first.
let the consecutive odd integers are :- x , x + 2 and x + 4.
According to question :-
the sum of the last two is 15 less than 5 times the first.
It means that
the sum of ( x + 2 ) and ( x + 4 ) is 15 less than 5 times the x .
( x + 2 ) + ( x + 4 ) = 5x - 15
x + 2 + x + 4 = 5x - 15
2x + 6 = 5x - 15
6 + 15 = 5x + 2x
21 = 7x
or ;
7x = 21
x = 21 / 7
x = 3
So, the consecutive odd numbers are :-
x = 3
x + 2 = 3 + 2 = 5
x + 4 = 3 + 4 = 7
=> 3 , 5 and 7
hope this helps you
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.