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Sagot :
Answer:
Given:- [tex]f(x)=\frac{x-3}{x+2}[/tex]
Solution:- [tex]\left(-\infty \:,\:-2\right)\cup \left(-2,\:\infty \:\right)[/tex]
So, Answer:- [tex]All \: real\: value \: of x\: such \; that \: \neq -2[/tex]
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