Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

At what point on the curve x = 6t2 + 6, y = t3 − 2 does the tangent line have slope 1 /2 ?

Sagot :

caylus

Answer:

Hello,

P=(30,6)

Step-by-step explanation:

[tex]x=6t^2+6\\y=t^3-2\\\\\dfrac{dx}{dt}= 12t\\\dfrac{dy}{dt}= 3t^2\\\\\dfrac{dy}{dx} =\dfrac{\dfrac{dy}{dt} }{\dfrac{dx}{dt} } =\dfrac{3t^2}{12t} =\dfrac{t}{4} \\\\\dfrac{t}{4} =\dfrac{1}{2} \Longrightarrow t=2\\\\\\x=6t^2+6=6*2^2+6=30\\\\y=t^3-2=2^2-2=8-2=6\\\\\\Tangence\ point=(30,6)\\[/tex]

The point on the curve x = 6t² + 6, y = t³ - 2 where the tangent line have slope 1/2 is (30, 6).

How to depict the point on the curve?

From the information given, x = 6t² + 6, y = t³ - 2. We'll find the first order derivative of x and y which will be:

dx/dt = 12t

dy/dt = 3t²

Therefore, 3t²/12t = t/4, t = 2.

We'll put the value of t back into the equations.

x = 6t² + 6,

x = 6(2)² + 6

x = 24 + 6 = 30

y = t³ - 2.

y = (2)³ - 2

y = 8 - 2 = 6

In conclusion, the correct options is (30, 6).

Learn more about slope on:

https://brainly.com/question/3494733

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.