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9. Write a polynomial function in factored form with zeros at -2, 5, and 6.
F(x) = (x + 2)(x - 5)(x - 6)
+
F(x) = x3 - 9x2 + 8x + 60
O
f(x) = (x - 2)(x + 5)(x + 6)
Flx) = x3 + 9x2 + 8x - 60

Sagot :

wegnerkolmp2741o

Answer:

f(x) = ( x+2)(x-5)(x-6)

Step-by-step explanation:

We can write the equation with zeros at b1,b2,b3

f(x) =a( x-b1)(x-b2)(x-b3)  where a is a constant and b1 b2 b3 are the zeros

f(x) = a( x- -2)(x-5)(x-6)

f(x) = a( x+2)(x-5)(x-6)

We can choose a since we are not given any more information about the function.  Let a = 1

f(x) = 1( x+2)(x-5)(x-6)

f(x) = ( x+2)(x-5)(x-6)

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