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The angle of the resultant vector is equal to
the inverse tangent of the quotient of the x-component divided by the y-component of the resultant vector
the inverse cosine of the quotient of the y-component divided by the x-component of the resultant vector.
the inverse cosine of the quotient of the x-component divided by the y-component of the resultant vector.
the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.

Sagot :

onyebuchinnaji

The angle of the resultant vector is equal to the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.

To find the angle of a resultant vector, the vector must be resolved into y-component and x-component.

  • The y-component of a vector is the product of the magnitude of the vector and the sine of the angle of the vector to the horizontal.
  • The x-component of a vector is the product of the magnitude of the vector and the cosine of the angle of the vector to the horizontal.

The angle of this resultant vector is also known as the direction of the vector.

Mathematically, the direction of a resultant vector is given as;

[tex]\theta = tan^{-1} (\frac{R_y}{R_x} )\\\\where;\\\\\theta \ is \ the \ direction \ of \ the \ resultant \ vetcor\\\\R_y \ is \ the \ magnitude \ of \ the\ vector \ resolved \ in \ y - direction\\\\R_x \ is \ the \ magnitude \ of \ the\ vector \ resolved \ in \ x - direction[/tex]

Therefore, the angle of the resultant vector is equal to the inverse tangent of the quotient of the y-component divided by the x-component of the resultant vector.

Lear more here: https://brainly.com/question/3224643

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