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Consider the equation 5(10)^(z/4)=32 Solve the equation for z, express the solution as a logarithm in base-10

Sagot :

jacob193

Answer:

[tex]\displaystyle z = 4\, \log_{10} \left(\frac{32}{5}\right)[/tex].

Step-by-step explanation:

Multiply both sides by [tex](1/5)[/tex] and simplify:

[tex]\displaystyle \frac{1}{5} \times 5\, (10)^{z/4} = \frac{1}{5} \times 32[/tex].

[tex]\displaystyle (10)^{z/4} = \frac{32}{5}[/tex].

Take the base-[tex]10[/tex] logarithm of both sides:

[tex]\displaystyle \log_{10}\left(10^{z/4}\right) = \log_{10} \left(\frac{32}{5}\right)[/tex].

[tex]\displaystyle \frac{z}{4} = \log_{10}\left(\frac{32}{5}\right)[/tex].

[tex]\displaystyle z = \log_{10}\left(\frac{32}{5}\right)[/tex].

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