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A jet travels 500 kilometers in 40 minutes with a tail wind. Returning, the jet takes 50 minutes to cover the same distance. What is the rate of the plan and the speed of the wind?

Sagot :

Answer:

675 km/hr and 75 km/hr

Step-by-step explanation:

Let the speed of plane in still air be x and the speed of wind be y.

ATQ, (x+y)*(40/60)=500 and (x-y)*(50/60)=500. Solving it, we get x=675 and y=75

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