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Sagot :
Answer:
[tex]15\pi[/tex]
Step-by-step explanation:
[tex] \frac{ \theta}{360} \times 2\pi \: r \\ \frac{150}{360} \times 2 \times \pi \times 18 \\ \frac{5400\pi}{360} \\ = 15\pi[/tex]
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