Answered

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Given the equation representing a nuclear reaction in
which X represents a nuclide:
232Th → He + x
Which nuclide is represented by X?
A) 236
B) 228
Ra
SS
C) 236
Ra
92
U
92
D) 228
.
Ss U

Sagot :

pstnonsonjoku

The nuclide represented as X is thorium and this is an alpha decay.

The equation shown represents an alpha decay. In an alpha decay, an alpha particle is given off.

The atomic number of the parent nuclide is greater than that of the daughter nuclide by two units while the mass number of the parent is greater than that of the daughter nuclide by four units.

Hence the equation occurs as follows;

[tex]\frac{232}{92} Th ------> \frac{228}{88} Ra + He[/tex]

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