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If x/y + y/x =2, Then 4x-4y-4 = ? ( Please show with full process and don't spam )​

Sagot :

[tex]\\ \sf\longmapsto \dfrac{x}{y}+\dfrac{y}{x}=2[/tex]

[tex]\\ \sf\longmapsto \dfrac{x^2+y^2}{xy}=2[/tex]

[tex]\\ \sf\longmapsto x^2+y^2=2xy[/tex]

[tex]\\ \sf\longmapsto x^2+y^2-2xy=0[/tex]

[tex]\boxed{\sf (a-b)^2=a^2-2ab+b^2}[/tex]

[tex]\\ \sf\longmapsto (x-y)^2=0[/tex]

[tex]\\ \sf\longmapsto x-y=\sqrt{0}[/tex]

[tex]\\ \sf\longmapsto x-y=0[/tex]

Now

[tex]\\ \sf\longmapsto 4x-4y-4[/tex]

  • take 4common

[tex]\\ \sf\longmapsto 4(x-y-4)[/tex]

  • Put the value

[tex]\\ \sf\longmapsto 4(0-4)[/tex]

[tex]\\ \sf\longmapsto 4(-4)[/tex]

[tex]\\ \sf\longmapsto -16[/tex]

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