Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
D
Step-by-step explanation:
for you to find x you first have to find the adjacent of the 45° angle you can do that by using the other triangle.using the sin ratio
sin60=opposite/hypotenuse
sin60=a/7√3
a=10.5
then after you have found the adjacent you can use the cos ratio
cos45=adjacent/hypotenuse
cos45=10.5/x
cos45x/cos45=10.5/cos45
x=14.849
which is the same as 21√2 over 2
I hope this helps
Answer:
D
Step-by-step explanation:
Using sine ratio in left right angled triangle to find the altitude a of the large triangle which is common to both right triangles and the exact value
sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] , then
sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{a}{7\sqrt{3} }[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )
2a = 21 ( divide both sides by 2 )
a = [tex]\frac{21}{2}[/tex]
Using the cosine ratio in the right side triangle and the exact value
cos45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then
cos45° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{a}{x}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )
x = [tex]\sqrt{2}[/tex] a = [tex]\sqrt{2}[/tex] × [tex]\frac{21}{2}[/tex] = [tex]\frac{21\sqrt{2} }{2}[/tex] → D
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.