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Sammy and Hannah are finalists in a cooking competition. For the final round, each of them will randomly select a card without replacement that will reveal what their star ingredient must be. Here are the available cards:
Cabbage
Spinach
Kale
Leeks
Carrots
Turnips

Cabbage
​

Leeks
​

​

Spinach
​

Carrots
​

​

Kale
​

Turnips
​

​

Sammy and Hannah both want to get leeks as their star ingredient. Sammy will draw first, followed by Hannah.
What is the probability that NEITHER contestant draws leeks?
Round your answer to two decimal places.

Sagot :

facundo3141592

The probability that neither of them draws the Leeks card is P = 4/6 = 0.667

Here we can assume that all the cards have the same probability of being randomly drawn.

The cards are:

  • Cabbage
  • Spinach
  • Kale
  • Leeks
  • Carrots
  • Turnips

So we have 6 cards. We want to find the probability that neither contestant draws the "Leeks" card.

Sammy draws first, the probability of drawing the Leeks card will be equal to the quotient between the number of Leeks cards (one) and the total number of cards (6).

Then the probability of drawing the leeks card is p = 1/6

This means that the probability of NOT drawing the leeks card is:

q = 1 - 1/6 = 5/6.

Now draws Hanna, now there are 5 cards in the deck (because one was already drawn). With the same approach as before, the probability of drawing the Leeks card is p = 1/5, then the probability of NOT drawing the card is:

q = 1 - 1/5 = 4/5.

The joint probability (this is, the probability of both of these events to happen together) is just the product of the individual probabilities.

Then the probability that neither of them draws the Leeks card is:

P = (4/5)*(5/6) = 4/6 = 0.667

If you want to learn more about probability, you can read:

https://brainly.com/question/24349426

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