Dan is Correct by concluding that adults spend a mean of 3 hours each day doing leisure and sports activities. because [tex]3.08[/tex] hours or [tex]3.09[/tex] hours which are the mean time of sample A and B is approximately equal to 3 hours
From the question we are told that:
Total Sample size [tex]n=500[/tex]
Dan's mean [tex]\=x_D= 3hr[/tex]
Bret's mean [tex]\=x_D= 4hr[/tex]
Generally, the Total hours spent doing leisure and sports activities is mathematically given by
For Sample A
[tex]T_a=(1*70)+(2*90)+(3*135)+(4*140)+(5*65)\\\\[/tex]
[tex]T_a=1540 hours[/tex]
For Sample B
[tex]T_b=(1*80)+(2*80)+(3*130)+(4*135)+(5*75)[/tex]
[tex]T_b=1545[/tex]
Therefore
Mean Time spent doing leisure and sports activities by an American Adult
For Sample A
[tex]T_A=\frac{T_a}{n}[/tex]
[tex]T_A=\frac{1540}{500}[/tex]
[tex]T_A=3.08[/tex] hours
[tex]T_A \approx 3[/tex] hours
For Sample B
[tex]T_A'=\frac{T_b}{n}[/tex]
[tex]T_A'=\frac{1545}{500}[/tex]
[tex]T_A'=3.09[/tex] hours
[tex]T_A' \approx 3[/tex] hours
In conclusion
Dan is Correct because [tex]3.08[/tex] or [tex]3.09[/tex] which are the mean time of sample A and B is approximately equal to [tex]3[/tex]
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