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Sagot :
life hack: if you own a TI-84 graphing calculator you can just input that into the calculator on the graphing part and then you see which equation’s graph matches the graph you were given in the problem.
Answer: Choice C
f(x) = 5x^2 + 25x + 30
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Explanation:
The roots, aka x intercepts, of this curve are x = -3 and x = -2. This is where the graph crosses the x axis.
Since x = -3 is a root, this makes x+3 a factor of the quadratic. Similarly, x = -2 leads to x+2 as another factor. I'm using the zero product property.
So far we have found that the polynomial is (x+3)(x+2). This isn't the full factorization because if we plugged x = -1 into that expression, then we would get
y = (x+3)(x+2)
y = (-1+3)(-1+2)
y = (2)(1)
y = 2
But we want y = 10 instead. So we must multiply that factorization by 5 to jump from 2 to 10 (i.e. 5*2 = 10)
Therefore, the full factorization of this parabola is y = 5(x+3)(x+2)
Now let's expand everything out and simplify
y = 5(x+3)(x+2)
y = 5(x^2+2x+3x+6)
y = 5(x^2+5x+6)
y = 5x^2+5*5x+5*6
y = 5x^2 + 25x + 30
Choice C is the final answer
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To check this, we can plug in x = -3 and we should get 0
y = 5x^2 + 25x + 30
y = 5(-3)^2 + 25(-3) + 30
y = 5(9) + 25(-3) + 30
y = 45 - 75 + 30
y = -30 + 30
y = 0
This proves that x = -3 is a root of y = 5x^2 + 25x + 30
I'll let you check x = -2. You should also get y = 0 when plugging this x value in.
Plugging x = -1 should lead to y = 10 as the last bit of confirmation. I'll let you check this one as well.
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