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Sagot :
Hi there!
2|x - 1| + 5 < 13
Begin by subtracting 5 from both sides:
2|x - 1| < 8
Divide both sides by 2:
|x - 1| < 4
Find both the positive and negative solutions:
x - 1 < 4
x < 5
-(x - 1) < 4
-x + 1 < 4
-x < 3
x > -3
[tex]Hello[/tex] [tex]There![/tex]
Let's solve your inequality step-by-step.
[tex]2(|x-1|)+5<13[/tex]
Step 1:
You must add -5 both sides.
[tex]2(|x-1|)+5+-5<13+-5[/tex]
[tex]2(|x-1|)<8[/tex]
Step 2:
You must divide both sides by 2.
[tex]\frac{2(|x-1|)}{2}[/tex] [tex] \leq \frac{8}{2}[/tex]
[tex]|x-1|<4[/tex]
Step 3:
Solve the Absolute Value.
[tex]|x-1|<4[/tex]
We know that x−1<4 and x−1>−4.
[tex]x-1<4[/tex] Condition 1.
[tex]x-1+1<4+1[/tex] (Add 1 to both sides)
[tex]x<5[/tex]
[tex]x-1>-4[/tex] (Condition 2)
[tex]x-1+1>-4+1[/tex] (Add 1 to both sides)
[tex]x>-3[/tex]
[tex]ANSWER![/tex]
[tex]x<5[/tex] [tex]and[/tex] [tex]x>-3[/tex]
Hopefully, this helps you!!
[tex]AnimeVines[/tex]
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