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Can someone please help me with these 3 questions?

Can Someone Please Help Me With These 3 Questions class=

Sagot :

25) First, find the amount of minutes in 2 hours. Note that there are 60 minutes in one hour:

2 x 60 = 120 minutes per 2 hours.

Next, the bacteria doubles every 20 minutes. 120/20 = 6, which means that the bacteria will double 6 times:

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 bacteria will be your answer.

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26) The Area of a circle = πr²

Set the equation:

400π = π(r + 2)²

First, divide common factors from both sides, or π.

(400π)/π = (π(r + 2)²)/π

400 = (r + 2)²

√400 = √(r + 2)²

r + 2 = √400

r + 2 = √(20 x 20)

r + 2 = 20

r + 2 (-2) = 20 (-2)

r = 20 - 2

r = 18

18 is your final answer.

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27)

The volume of a box can be found by multiplying length x width x height:

[tex]V (box) = l * w * h[/tex]

The volume given is 90, the height 3, and the width is 1 foot less then length:

First solve what you know:

[tex]V(box) = 90\\h = 3\\l = l\\w = l - 1[/tex]

Plug in the corresponding terms with the corresponding variable. Isolate the variable, l. Divide 3 from both sides of the equation:

[tex]90 = 3 * l (l - 1)\\\frac{90}{3} = \frac{3 * l(l -1)}{3}\\30 = l(l - 1)\\[/tex]

Distribute l to both terms in the parenthesis:

[tex]30 = l(l - 1)\\30 = l^2 - l[/tex]

Solve:

[tex]30 = (6)^{2} -6\\30 = 36 - 6\\30 = 30[/tex]

∴ [tex]l = 6[/tex]

Solve for width. Width is 1 less foot then length:

[tex]l - 1 = w\\l = 6\\[/tex]

∴ [tex]6 - 1 = w\\w = 5[/tex]

Equation: [tex]V (box) = l * w * h[/tex]

or

[tex]l = \frac{V(box)}{w * h}[/tex]

[tex]V(box) = 90\\h = 3\\l = 6\\w = 5[/tex]