keojaylen15
Answered

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Suppose a shoe company estimates that its monthly cost is
C(x) = 300c2 + 200c and its monthly revenue is
R(x) = -0.5x3 + 900x2 – 500x + 400, where x is in thousands of pairs
of shoes sold. The profit is the difference between the revenue and the cost.
What is the profit function, P(x)?
O
A. P(x) = -0.5x3 + 600x2 – 700x + 400
B. P(2) = -0.5x3 + 1200x2 – 300x + 400
O C. P(x) = 0.523 + 60022 – 700.0 + 400
O D. P(x) = 0.523 – 600x2 + 700x – 400
PREVIOUS
I

Sagot :

caylus

Answer:

Hello,

Answer B

Step-by-step explanation:

[tex]C(x)=300*x^2+200*x\\\\R(x)=-0.5*x^3+900*x^2-500*x+400\\\\\\P(x)=R(x)-C(x)\\\\=-0.5*x^3+900*x^2-500*x+400-(300*x^2+200*x)\\\\=-0.5x^3+900x^2-300x^2-500x-200x+400\\\\=-0.5x^3+600x^2-700x+400\\[/tex]

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